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Question
junior college 2 | H2 Maths
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How do part 2…
Date Posted: 7 months ago
Views: 111
z = k exp(iα)
w* = 3k² exp(-i4α)
z/w* = [k exp(iα)]/[3k² exp(-i4α)]
= 1/(3k) exp(i5α)
= 1/(3k) cos(5α) + i 1/(3k) sin(5α)
w* = 3k² exp(-i4α)
z/w* = [k exp(iα)]/[3k² exp(-i4α)]
= 1/(3k) exp(i5α)
= 1/(3k) cos(5α) + i 1/(3k) sin(5α)
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done
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Pls let me know if this makes sense.
Date Posted:
7 months ago
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