Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
junior college 2 | H2 Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
pls helpp
Date Posted: 1 month ago
Views: 56
1) Equivalent to arranging 1P 3A 1Y: 5!/3!
2i) 7C3 × 6C3
2ii) Using the complement method:
Total ways with no restrictions - both A and B are chosen = 7C3 × 6C3 - 6C2 × 5C2
3i) Equivalent to selecting 4 letters from 7: 7P4
3ii) Equivalent to selecting 1 of 2 pairs of repeated letters and 2 of 5 non-repeating letters: 2C1 × 5C2 × 4!/2!
3iii) 3 possible cases, no repeats, 1 repeat and 2 repeats: 7P4 + 2C1 × 5C2 × 4!/2! + 4!/(2!2!)
2i) 7C3 × 6C3
2ii) Using the complement method:
Total ways with no restrictions - both A and B are chosen = 7C3 × 6C3 - 6C2 × 5C2
3i) Equivalent to selecting 4 letters from 7: 7P4
3ii) Equivalent to selecting 1 of 2 pairs of repeated letters and 2 of 5 non-repeating letters: 2C1 × 5C2 × 4!/2!
3iii) 3 possible cases, no repeats, 1 repeat and 2 repeats: 7P4 + 2C1 × 5C2 × 4!/2! + 4!/(2!2!)
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
answered
Date Posted:
4 weeks ago
360 Tutoring Program