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primary 6 | Maths
| Fractions
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Date Posted: 1 month ago
Views: 57
#backwards
#total unchanged - internal transfer
360÷3 = 120
in the end
【after ⅕C → A】
A:B:C(⅘) = 120:120:120
120÷4=30
change #2
【after ⅓B → C】
A=120-30=90
C=120+30 = 150
A:B(⅔):C = 90:120:150
120÷2 = 60
change #1
【after ⅙A → B】
B=120+60=180
C=150-60 = 90
A(⅚):B:C = 90:180:90
90÷5 = 18
at first
A=90+18=108
B=180-18 = 162
A:B:C = 108:162:90
#total unchanged - internal transfer
360÷3 = 120
in the end
【after ⅕C → A】
A:B:C(⅘) = 120:120:120
120÷4=30
change #2
【after ⅓B → C】
A=120-30=90
C=120+30 = 150
A:B(⅔):C = 90:120:150
120÷2 = 60
change #1
【after ⅙A → B】
B=120+60=180
C=150-60 = 90
A(⅚):B:C = 90:180:90
90÷5 = 18
at first
A=90+18=108
B=180-18 = 162
A:B:C = 108:162:90
See 2 Answers
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Date Posted:
1 month ago
Thanks :)
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