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primary 6 | Maths
| Geometry
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Geometry question
Date Posted: 8 months ago
Views: 129
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I see that you have stated angle GCD = ECB=50. This is incorrect cos BCG is not a straight line.
AB is parallel to CD. So using interior opp. Angles =180, angle DCB= 180-68=112.
Angle ECB=180-113=68(angle on a str line)
The triangle is isosceles.
(180-68)/2=56
56+68=124degrees
AB is parallel to CD. So using interior opp. Angles =180, angle DCB= 180-68=112.
Angle ECB=180-113=68(angle on a str line)
The triangle is isosceles.
(180-68)/2=56
56+68=124degrees
Thank you.
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