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secondary 4 | A Maths
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I have the answers to this qn but I don’t understand this one specific part—>When u get to the part when sin2x=0, 2x will be 0, pi, 2 pi, (0–2pi) or (pi—2pi). I can understand where the first 3 values come from but I don’t understand where the (0–2pi) or (pi—2pi) come from. Can someone pls explain
Date Posted: 8 months ago
Views: 69
You need to “go back one round” the A-S-T-C diagram to pick up more angles, since our required solutions for x must lie between “-pi and pi”, not “0 and pi”.
Going back one round requires us to subtract 2pi from our two solutions obtained (to get another two solutions).
Going back one round requires us to subtract 2pi from our two solutions obtained (to get another two solutions).
Ohhhh I see now. Thanks a lot !
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The range of x is from -pi to pi. So the angle turns clockwise AND anticlockwise directions.
Hope this helps.
Hope this helps.
Date Posted:
8 months ago
Ohhhh i understand now. Tjank you so much!!:)
Fhanks
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