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For 6iii
Date Posted:
8 months ago
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For 6iv. I used the shoelace method which you can find online. The formula looks ridiculous but it's a simple concept:
1/2[X1(Y2-Y3] because when you look at the X1 vertice the other Y coordinates are Y2 and Y3. Same for 1/2[X2(Y1-Y3] because when you look at the X2 vertices the other Y coordinates shown in the triangle is Y1 and Y3.
1/2[X1(Y2-Y3] because when you look at the X1 vertice the other Y coordinates are Y2 and Y3. Same for 1/2[X2(Y1-Y3] because when you look at the X2 vertices the other Y coordinates shown in the triangle is Y1 and Y3.
Date Posted:
8 months ago
thank you!