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secondary 3 | E Maths
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Please explain why angle BCS is 48°, instead of angle SBC. Thanks
Date Posted: 11 months ago
Views: 125
For n sided regular polygon, AB=BC
For regular hexagon, AB= BS
Therefore, BC=BS
∠BCD = ∠BSC = 48° for isosceles triangle.
Hope this helps
For regular hexagon, AB= BS
Therefore, BC=BS
∠BCD = ∠BSC = 48° for isosceles triangle.
Hope this helps
Thank you
See 1 Answer
For n sided regular polygon, AB=BC
For regular hexagon, AB= BS
Therefore, BC=BS
∠BCD = ∠BSC = 48° for isosceles triangle.
Hope this helps
For regular hexagon, AB= BS
Therefore, BC=BS
∠BCD = ∠BSC = 48° for isosceles triangle.
Hope this helps
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