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secondary 3 | A Maths
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Can someone explain to me how does the coeff of x^2 > 0 and f(x) > 0 lead to there having no real roots? I stared and read that sentence 20 times and still dont get it. Pls help
Date Posted: 1 year ago
Views: 191
Yes! When the coefficient of \( x ^ 2 \) is much more substantial than no (suggesting the graph opens up upwards) plus \( f(x) \) is more than no it indicates that the chart of the quadratic feature exists totally over the x-axis. Given that the , parabola does not go across the x-axis it has no actual origins. This principle is commonly gone over in Higher education dissertation topics pertaining to algebraic features and also chart concept.
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Hope this helps
Date Posted:
1 year ago
Ohh so when f(x) > 0, there wont be any real roots because the curve will never cut thru the x axis?
Yes basically f(x) is the y coordinate. F(x) >0 means all y coordinates >0, thus the curve does not intersect with the x axis
OHHH okay thank you!!!
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