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junior college 1 | H2 Maths
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Date Posted: 9 months ago
Views: 193
50 = rθ + 2r
θ = 50/r - 2
dθ/dt = -50/r² × dr/dt = -50/10² × -5 = 5/2 radians per second.
A = 1/2r²θ = 1/2 r²(50/r - 2) = 25r - r²
dA/dt = (25 - 2r) × dr/dt = 5 × -5 = -25 cm² per second.
θ = 50/r - 2
dθ/dt = -50/r² × dr/dt = -50/10² × -5 = 5/2 radians per second.
A = 1/2r²θ = 1/2 r²(50/r - 2) = 25r - r²
dA/dt = (25 - 2r) × dr/dt = 5 × -5 = -25 cm² per second.
See 2 Answers
Implicit differentiation approach :)
done
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clear
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Hi, every time I see a differentiation question with respect to time, I immediately try to express the required thing (d0/dt) as a product or division of two other things (d0/dr * dr/dt).
Although treating the two things like fractions isn't right, it helps in solving these type of questions.
Although treating the two things like fractions isn't right, it helps in solving these type of questions.
Date Posted:
9 months ago
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