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primary 5 | Maths
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Date Posted: 10 months ago
Views: 87
Distance of track A and B combined
= 1 5/8 + 3 4/5
= 1 25/40 + 3 32/40
= 4 57/40
= 5 17/40
Distance covered in 1 day
= 5 17/40 × 2
= 10 34/40
= 10 17/20
So in 6 days,
10 17/20 × 6
= 60 102/20
= 65 2/20
= 65 1/10
= 1 5/8 + 3 4/5
= 1 25/40 + 3 32/40
= 4 57/40
= 5 17/40
Distance covered in 1 day
= 5 17/40 × 2
= 10 34/40
= 10 17/20
So in 6 days,
10 17/20 × 6
= 60 102/20
= 65 2/20
= 65 1/10
Alternatively,
If each track is walked by the ranger twice daily for 6 days,
2 × 6 = 12
Each track is walked 12 times in total.
For Track A,
12 × 1 5/8
= 12 60/8
= 19 4/8
= 19 1/2
For Track B,
3 4/5 × 12
= 36 48/5
= 45 3/5
Total
= 19 1/2 + 45 3/5
= 19 5/10 + 45 6/10
= 64 11/10
= 65 1/10
If each track is walked by the ranger twice daily for 6 days,
2 × 6 = 12
Each track is walked 12 times in total.
For Track A,
12 × 1 5/8
= 12 60/8
= 19 4/8
= 19 1/2
For Track B,
3 4/5 × 12
= 36 48/5
= 45 3/5
Total
= 19 1/2 + 45 3/5
= 19 5/10 + 45 6/10
= 64 11/10
= 65 1/10
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Refer to main comments for more explanation by @J. Hope this helps ♦
Date Posted:
10 months ago
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