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secondary 4 | A Maths
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Pls help
Date Posted: 1 year ago
Views: 261
Looks more like H2 Math to me
Idea is to work backwards.
Since at II there is a scaling of factor 2 in the direction of the y-axis,
Scale by ½ to reverse this.
y = 6 cos x → y = ½(6 cos x) = 3 cos x
Next, I mentions a translation of π/4 units in the direction of the positive x-direction.
To reverse this, translate π/4 units in the other direction (negative x -direction)
When you translate in the negative x-direction, you do an addition to the x term.
y = 3 cos x → y = 3 cos (x + π/4)
Therefore,
h(x) = 3 cos (x + π/4)
Since at II there is a scaling of factor 2 in the direction of the y-axis,
Scale by ½ to reverse this.
y = 6 cos x → y = ½(6 cos x) = 3 cos x
Next, I mentions a translation of π/4 units in the direction of the positive x-direction.
To reverse this, translate π/4 units in the other direction (negative x -direction)
When you translate in the negative x-direction, you do an addition to the x term.
y = 3 cos x → y = 3 cos (x + π/4)
Therefore,
h(x) = 3 cos (x + π/4)
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