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secondary 4 | A Maths
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Date Posted: 1 year ago
Views: 267
(i) application of the distance formula
Distance of AB = Distance of BC = sqrt((15-14)^2 + (k-8)^2)
(ii) BD is the angle bisector of AC i.e. is passes through the midpoint of AC
(iii) Shoelace Method
Distance of AB = Distance of BC = sqrt((15-14)^2 + (k-8)^2)
(ii) BD is the angle bisector of AC i.e. is passes through the midpoint of AC
(iii) Shoelace Method
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