①Taking ABCD to be in a clockwise manner.

From A(2,3) to B(6,6),

Run = 6 - 2 = 4
Rise = 6 - 3 = 3

Gradient = 3/4

For the opposite side DC,the run and rise must be the same since the length and gradients are equal to AB's.

The other two sides, BC and AD are parallel to each other. But they are also perpendicular to AB and DC.

Since product of gradients of two perpendicular lines = -1,

Gradient of BC and AD = -1/¾ = -4/3

Essentially, the rise and run are opposite from AB and DC. But the rise has a negative sign since BC and AD are sloping downwards.

From B, move 3 units to the right and 4 units down to get coordinates of C.

B(6,6) → C(9,2)

From A, do the same translation.

A(2,3) → D(5,-1)

②Taking ABCD to be in an anticlockwise manner.

Now DC is above AB rather than below it in case ①

Using the same gradient, the translation from B to C is now upwards and leftwards , instead of downwards and rightwards.


From B, move 3 units to the left and 4 units up to get coordinates of C.

B(6,6) → C(3,10)

From A, do the same translation.

A(2,3) → D(-1,7)