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secondary 4 | A Maths
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Pls help
D = a lg(P/b)
D = a (lg P - lg b)
D = a lg P - a lg b
This is analogous to the equation of a straight line y = mx + c , whereby :
D is the dependent variable. (analogous to y)
a is the gradient of the line. (analogous to m)
lg P is the independent variable. (analogous to x)
-a lg b is the intercept of the vertical axis or the D-intercept in this case. (analogous to c)
(Note that since both a and b are constants,
-a lg b is constant as well)
We will plot D against lg P to obtain a straight line.
Choose the coordinates of any two points on the line. Call them (lg P₁ , D₁) and (lg P₂ , D₂)
Find the ratio of the vertical change over the horizontal change.
a = gradient of line = (D₂ - D₁) / (lg P₂ - lg P₁)
By reading the value of the D-intercept, we can get the value of -a lg b
Eg. The D-intercept = some value k
k = -a lg b
lg b = -k/a
b = 10^(-k/a)
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