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secondary 3 | A Maths
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Date Posted: 1 year ago
Views: 253
Just carry out long division. P(x) is the quotient, k is the remainder. Divide by x+1
Alternatively, you can split out or rewrite the terms such that (x + 1) can be factored out.
I've shown this earlier but apparently your earlier post has been deleted.
f(x) = 2x³ - 12x² + 17x + 3
= 2x³ + 2x² - 14x² + 17x + 3
= 2x²(x + 1) - 14x² - 14x + 31x + 3
= 2x²(x + 1) - 14x(x + 1) + 31x + 31 - 28
= 2x²(x + 1) - 14x(x + 1) + 31(x + 1) - 28
Now we can factor out (x + 1)
= (x + 1)(2x² - 14x + 31) - 28
P(x) = 2x² - 14x + 31
k = -28
I've shown this earlier but apparently your earlier post has been deleted.
f(x) = 2x³ - 12x² + 17x + 3
= 2x³ + 2x² - 14x² + 17x + 3
= 2x²(x + 1) - 14x² - 14x + 31x + 3
= 2x²(x + 1) - 14x(x + 1) + 31x + 31 - 28
= 2x²(x + 1) - 14x(x + 1) + 31(x + 1) - 28
Now we can factor out (x + 1)
= (x + 1)(2x² - 14x + 31) - 28
P(x) = 2x² - 14x + 31
k = -28
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Answer given in the other comments section
Yet to learnt that method
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