Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
primary 5 | Maths
| Whole Numbers
2 Answers Below
Anyone can contribute an answer, even non-tutors.
Please help. Thanks
2 + 4 + 6 + 8 + 10 + 12
1st 2nd 3rd 4th 5th 6th
Just realise each number is twice the value of its position.
So the 30th number is: 30 × 2 = 60
Then apply the pairing method.
Sum
= 2 + 4 + 6 + 8 + 10 + 12 + ... + 30th number
We can observe that for the first 6 numbers,
2 + 4 + 6 + 8 + 10 + 12
1st 2nd 3rd 4th 5th 6th
Factor out 2,
= 2 × (1 + 2 + 3 + 4 + 5 + 6)
From this we can clearly see that each number in the bracket is the same as its position.
So for the sum of the first 30 numbers, we know that the last number in the bracket is 30.
Sum = 2 × (1 + 2 + 3 + 4 + 5 + 6 +... + 30)
= (1 + 2 + 3 + 4 + 5 + 6 +... + 30)
+ (1 + 2 + 3 + 4 + 5 + 6 +... + 30)
Basically it's as good as saying we split each number equally into two parts.
This can be rearranged into:
(1 + 2 + 3 + 4 + 5 + 6 +... + 30)
(30+29+28+27+26 25+...+1)
We pair the numbers in the top bracket with the corresponding number in the bottom bracket.
1 + 30 = 31
2 + 29 = 31
3 + 28 = 31
...
15 + 16 = 31
16 + 15 = 31
...
28 + 3 = 31
29 + 2 = 31
30 + 1 = 31
We have two sets of the bracket, so we can get 30 pairs of 31.
Total = 31 × 30 = 930
See 2 Answers