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secondary 4 | A Maths
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please help me with this amath question
The idea now is to move all the terms with power x to the left.
Based on your working, you could start with :
16ˣ × 25ˣ / 25 = (4³/²)ˣ / 4 × 5ˣ / 5
Then,
16ˣ × 25ˣ / 25 = (√4³)ˣ × 5ˣ / (4×5)
16ˣ × 25ˣ / 25 = (√64)ˣ × 5ˣ / 20
16ˣ × 25ˣ / 25 = 8ˣ × 5ˣ / 20
16ˣ × 25ˣ / (8ˣ × 5ˣ) = 25 / 20
(16 × 25 / (8×5) )ˣ = 5/4
10ˣ = 5/4
(10ˣ)² = (5/4)²
(10²)ˣ = 5²/4²
100ˣ = 25/16
Or you could start with :
16ˣ × 25ˣ / 25 = (4¹/²)³ˣ/ 4 × 5ˣ / 5
16ˣ × 25ˣ / 25 = (√4)³ˣ × 5ˣ / (4 × 5)
16ˣ × 25ˣ / 25 = (2)³ˣ × 5ˣ / 20
16ˣ × 25ˣ / 25 = 8ˣ × 5ˣ / 20
Continue the steps as previously shown above.
100ˣ = 25/16
We can reuse the earlier result :
10ˣ = 5/4
x = lg(5/4) or lg(1.25)
x ≈ 0.0969 (3s.f)
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