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secondary 3 | A Maths
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Polynomial theorem question. Help please
Date Posted: 11 months ago
Views: 154
Rewrite 49 as 48 + 1.
49^15 - 1
= (48 + 1)^15 - 1
= 48^15 + … + 1^15 - 1
In the expansion of (48 + 1)^15, there are a total of 15 out of the 16 terms which contains at least one power of 48. Only the last term in the expansion, 1^15, does not. This is negated by the “- 1” at the end, so now all the terms will be multiples of 48, so they are going to be divisible by 8 as well.
49^15 - 1
= (48 + 1)^15 - 1
= 48^15 + … + 1^15 - 1
In the expansion of (48 + 1)^15, there are a total of 15 out of the 16 terms which contains at least one power of 48. Only the last term in the expansion, 1^15, does not. This is negated by the “- 1” at the end, so now all the terms will be multiples of 48, so they are going to be divisible by 8 as well.
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Hope this helps. Regards
Date Posted:
11 months ago
Thank you very much
My pleasure. Regards
Thank you very much
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