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secondary 4 | E Maths
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thx
Let Min's money at first be $5x
Let Brian's money at first be $3x
Min's money now = $(5x - 22)
Brian's money now = $(3x + 22)
Since the ratio of Min's money to Brian's money now is 3:4, we can rewrite this in fraction form.
(Min's money now) / (Brian's money now) = 3 / 4
(5x - 22) / (3x + 22) = 3 / 4
Cross multiply,
4(5x - 22) = 3(3x + 22)
20x - 88 = 9x + 66
20x - 9x = 66 + 88
11x = 154
x = 154/11
x = 14
Amount of money Min has now
= $(5 × 14 - 22)
= $48
Total amount is unchanged, internal transfer (This is like a PSLE method)
Make the total units the same for both ratios.
At first
Min $ : Brian $ : Total
5 : 3 : 8
35 : 21 : 56
Now
Min $ : Brian $ : Total
3 : 4 : 7
24 : 32 : 56
Let Min's money at first be $35x
Min's money now = $24x
Change in amount = $35x - $24x = $11x
$11x = $22
x = $22/11
x = 2
Min's money now = $(24 x 2) = $48
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