Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
primary 6 | Maths
| Fractions
One Answer Below
Anyone can contribute an answer, even non-tutors.
Assist pls
Date Posted: 1 year ago
Views: 203
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Try
Total unchanged
Total unchanged
Date Posted:
1 year ago
I don’t understand your 2nd part answers? Why you choose the total unit to be 60? Why if we don’t find the common factor of the boy which is 4unit and 9unit for competor, which is common factor of 4 and 9 is 36???, I don’t understand why you chose the 12 becoming 60 unit???
12 is the LCM of 3, 4 , cos of total unchanged, so we have to align the number same
Can you understand this ?
Can you understand this ?
The LCM can be 36 too? Because 12x3= 36 too, just don’t understand why the LCM is 60, where 36 can be also too right??
Good question upto here
After align the total as 12u
Boys total is 4u, right?
60%×4u=3/5 ×4u is not a whole number, is it?
So 5×4u=20u
60%×20u=12u
After align the total as 12u
Boys total is 4u, right?
60%×4u=3/5 ×4u is not a whole number, is it?
So 5×4u=20u
60%×20u=12u
36 is based on (4,9)
first , it does not mk sense, cos the item that we hv to align as same is total
NOT boy and non-competitor
2nd
do u think the 36 can hv u the whole number w multiplying 60%, as 36 is the boys in total?
60% × 36
= 0.6×36
= ⅗ ×36
first , it does not mk sense, cos the item that we hv to align as same is total
NOT boy and non-competitor
2nd
do u think the 36 can hv u the whole number w multiplying 60%, as 36 is the boys in total?
60% × 36
= 0.6×36
= ⅗ ×36
360 Tutoring Program