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primary 6 | Maths
| Data Analysis
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Date Posted: 1 year ago
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Date Posted:
1 year ago
Thanks so much
For b),
You can assume all are 20¢ coins,
Total money = 20×20¢ = 4.00
Short of = 6.40-4.00 = 2.40
Difference of 50¢ & 20¢ = 30¢
Therefore, 50¢ coins have 2.40÷$0.30= 8 coins
You can assume all are 20¢ coins,
Total money = 20×20¢ = 4.00
Short of = 6.40-4.00 = 2.40
Difference of 50¢ & 20¢ = 30¢
Therefore, 50¢ coins have 2.40÷$0.30= 8 coins
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