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Question
primary 6 | Maths
| Fractions
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Date Posted: 1 year ago
Views: 168
concept
excess / shortage
- number of student is fixed (u)
- total unchanged
8u+6 = 10u-240 = original total sweet
10u - 8u = 2u
6+240 = 246
(a)
1u = 246÷2 = 123 (Ans)
(b)
8u+6 = 10u-240
= 990 (Ans)
excess / shortage
- number of student is fixed (u)
- total unchanged
8u+6 = 10u-240 = original total sweet
10u - 8u = 2u
6+240 = 246
(a)
1u = 246÷2 = 123 (Ans)
(b)
8u+6 = 10u-240
= 990 (Ans)
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same question type
UR QN
concept
excess / shortage
- number of student is fixed (u)
- total unchanged
8u+6 = 10u-240 = original total sweet
10u - 8u = 2u
6+240 = 246
(a)
1u = 246÷2 = 123 (Ans)
(b)
8u+6 = 10u-240
= 990 (Ans)
UR QN
concept
excess / shortage
- number of student is fixed (u)
- total unchanged
8u+6 = 10u-240 = original total sweet
10u - 8u = 2u
6+240 = 246
(a)
1u = 246÷2 = 123 (Ans)
(b)
8u+6 = 10u-240
= 990 (Ans)
Date Posted:
1 year ago
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