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primary 6 | Maths
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I got 228 as answer. But correct answer is 229. Please assist.
Date Posted: 1 year ago
Views: 201
ABACA
ABACA
ABACA
…
137 / 3 = 45 R 2
There will be 45 sets of ABACA (135 As) plus a further ABAC.
Total number of letters
= 225 + 4
= 229
ABACA
ABACA
…
137 / 3 = 45 R 2
There will be 45 sets of ABACA (135 As) plus a further ABAC.
Total number of letters
= 225 + 4
= 229
Oh, we don't stop at ABA ?
No. Greatest possible letters is ABAC for 137 A(s).
If lease possible, then stop at ABA.
If lease possible, then stop at ABA.
Basically, adding a C behind increases the total letter count without increasing the number of As in the list.
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done
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I think your mistake is that you did not include the 4th letter C but since qn asked for greatest possible C should be included so it's 229 instead of 228
Date Posted:
1 year ago
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