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For perfect cube, the powers of prime factors have to be multiples of 3. Hope this helps! ;))
Date Posted:
1 year ago
Thanks for solving, but the answer for (b) is incorrect.
Oops, didn't see the perfect square part,I just uploaded another solution for (b). Ignore the (b) in this one.
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Perfect cube and perfect square = powers of prime factors have to be multiples of 2 and 3 (smallest 6). Hope this helps! ;))
Date Posted:
1 year ago
May I know how to get 2^6 x 3^6 x 5^6? Thank you!
In order for 360k to be a perfect square and perfect cube, all the powers of the prime factors have to be power of 6.