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Question
primary 6 | Maths
| Ratio
3 Answers Below
Anyone can contribute an answer, even non-tutors.
Thanks in advance
Date Posted: 1 year ago
Views: 189
Concept
Total unchanged
1+4=5
3+5=8
LCM (5,8)=40
A=8×1=8
B=5×3=15
C=40-8-15=17
C-B=17-15=2
2:40=$90:$1800
Ans: $1800
Total unchanged
1+4=5
3+5=8
LCM (5,8)=40
A=8×1=8
B=5×3=15
C=40-8-15=17
C-B=17-15=2
2:40=$90:$1800
Ans: $1800
See 3 Answers
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total unchanged
model method
LCM
model method
LCM
Date Posted:
1 year ago
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total unchanged
fraction method
fraction method
Date Posted:
1 year ago
Thanks
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Personally i dont like doing modelling thats why i didnt do it by models (and i actually dk how to do by that haha cuz i dont use it) but the second method works for me the best
Date Posted:
1 year ago
The point is for the students to realise that the total should remain unchanged (since it involves the same people), but the first ratio shows that the total is “5” while the second ratio shows that the total is “8” (so there is kind of a “conflict” with the “unchanged” clause).
In this case drawing the model would require us to divide the “5” and the “8” until we see 40 equal lengths each, but I think that cutting the model into 40 equal lengths each is not reasonable for an average student.
By the time a P5 student gets into P6, the model diagrams become very hard to draw, and that is the point where model drawings start to be less frequently used.
In this case drawing the model would require us to divide the “5” and the “8” until we see 40 equal lengths each, but I think that cutting the model into 40 equal lengths each is not reasonable for an average student.
By the time a P5 student gets into P6, the model diagrams become very hard to draw, and that is the point where model drawings start to be less frequently used.
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