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primary 5 | Maths
| Whole Numbers
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Date Posted: 1 year ago
Views: 117
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1 set of coin consist of 4 20¢ coins and 1 5p¢ coin
Total value of 1 set = 4×$0.20+$0.50 = $1.30
Number of sets = $39÷$1.30 = 30
Total number of coins = 30×5 = 150
Total value of 1 set = 4×$0.20+$0.50 = $1.30
Number of sets = $39÷$1.30 = 30
Total number of coins = 30×5 = 150
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