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Question
secondary 3 | E Maths
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am I correct?
Date Posted: 1 year ago
Views: 270
(a)
(x-1)∙(x+2) = (2x-5)∙(x-6)
x²+x-2 = 2x²-17x+30
x² - 18x + 32 = 0
(x-16)∙(x-2) = 0
x₁ = 16
x₂ = 2
(x-1)∙(x+2) = (2x-5)∙(x-6)
x²+x-2 = 2x²-17x+30
x² - 18x + 32 = 0
(x-16)∙(x-2) = 0
x₁ = 16
x₂ = 2
(b)
3(7-x)∙(x-1)-3(x+2) = (x+2)∙(x-1)
3(7-x)∙(1-x)+3(x+2) = (x+2)∙(1-x)
3(x²-8x+7) + 3x+6 = -x² - x + 2
4x² - 20x + 25 = 0
(2x-5)² = 0
x = 2.5
3(7-x)∙(x-1)-3(x+2) = (x+2)∙(x-1)
3(7-x)∙(1-x)+3(x+2) = (x+2)∙(1-x)
3(x²-8x+7) + 3x+6 = -x² - x + 2
4x² - 20x + 25 = 0
(2x-5)² = 0
x = 2.5
my answers are correct then?
Yes
Both r correct
Both r correct
See 1 Answer
done
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clear
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can factorise, no need to use the formula
Date Posted:
1 year ago
oh alright thank you
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