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## Question

secondary 3 | E Maths

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am I correct?

(x-1)∙(x+2) = (2x-5)∙(x-6)

x²+x-2 = 2x²-17x+30

x² - 18x + 32 = 0

(x-16)∙(x-2) = 0

x₁ = 16

x₂ = 2

3(7-x)∙(x-1)-3(x+2) = (x+2)∙(x-1)

3(7-x)∙(1-x)+3(x+2) = (x+2)∙(1-x)

3(x²-8x+7) + 3x+6 = -x² - x + 2

4x² - 20x + 25 = 0

(2x-5)² = 0

x = 2.5

Both r correct

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