Ask Singapore Homework?

Upload a photo of a Singapore homework and someone will email you the solution for free.



Question

secondary 3 | A Maths
One Answer Below

Anyone can contribute an answer, even non-tutors.

Answer This Question
Alaya
Alaya

secondary 3 chevron_right A Maths chevron_right Singapore

Pls help thx

Date Posted: 1 year ago
Views: 176
Eric Nicholas K
Eric Nicholas K
1 year ago
When an expression x² + 2kx + k² - 5k + 7 is always positive for all real values of x, its output value can never be zero. This is because zero is a non-positive figure.

In other words, there cannot be any real roots (solution) to the equation x² + 2kx + k² - 5k + 7 = 0.

[Graphically, this means that the curve y = x² + 2kx + k² - 5k + 7 will always lie above the x-axis and will never touch or cut the x-axis at all]

So, the discriminant of roots will be negative.

Discriminant < 0

But what is our discriminant? It's (2k)² - 4 (1) (k² - 5k + 7), or simply 20k - 28.

So, 20k - 28 < 0
20k < 28
k < 1.4

See 1 Answer

done {{ upvoteCount }} Upvotes
clear {{ downvoteCount * -1 }} Downvotes
Ng Wei Jie Wilcent
Ng Wei Jie Wilcent's answer
177 answers (Tutor Details)
1st