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For a reference only
Date Posted:
1 year ago
The line du/dx = (u² + 1) / (u - 1) is correct, but I doubt the integration can be performed that way.
This is in contrast to the expression du/dx = (x² + 1) / (x - 1) which can be integrated using your approach.
This is in contrast to the expression du/dx = (x² + 1) / (x - 1) which can be integrated using your approach.
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Unless my working went very horribly wrong somewhere, I don’t think we can express y in terms of x for this question.
Date Posted:
1 year ago