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secondary 3 | E Maths
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Rosie
Rosie

secondary 3 chevron_right E Maths chevron_right Singapore

Pls help asap ty

Date Posted: 1 year ago
Views: 202
sstrike
Sstrike
1 year ago
by completing the square

(a)
-x²+6x+5 = 0

x²-6x = 5
(x-3)² = 5+3² = 14

x = 3±√14 (Ans)


(b)
2x²-8x+14 = 0

x²-4x+7 = 0

x²-4x = -7
(x-2)² = 2²-7 = -3

x = 2±√(-3) (Ans)
Rosie
Rosie
1 year ago
So is there no solution? -3 cannot be square root?
sstrike
Sstrike
1 year ago
-3 is negative
so the answer will be complex numbers
Stephen Su Quan Yuan
Stephen Su Quan Yuan
1 year ago
Therefore need to reject and hence, no real solutions at all. Our secondary school syllabus covers only real numbers. We don’t study complex numbers at secondary school level.

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Stephen Su Quan Yuan
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