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secondary 4 | E Maths
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Date Posted: 1 year ago
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The relative atomic mass of propane, C3H8, is 44 (basically, 3 x 12 + 8 x 1)
Number of moles of C3H8 present
= 0.88 / 44
= 0.02
In 0.02 mol of C3H8, there are 0.02 x 6 x 10^23, or 1.2 x 10^22, C3H8 molecules.
But in each C3H8 molecule, there are eight H atoms.
Number of H atoms needed
= 8 x 1.2 x 10^22
= 9.6 x 10^22
Number of moles of C3H8 present
= 0.88 / 44
= 0.02
In 0.02 mol of C3H8, there are 0.02 x 6 x 10^23, or 1.2 x 10^22, C3H8 molecules.
But in each C3H8 molecule, there are eight H atoms.
Number of H atoms needed
= 8 x 1.2 x 10^22
= 9.6 x 10^22
See 1 Answer
Mr of C3H8 = 12 x 3 + 8 = 44
mols of C3H8 = 0.88/44 = 0.02 mols
Number of H atoms = 8 x 0.02 x 6 x 10^23
= 9.6 x 10^22
mols of C3H8 = 0.88/44 = 0.02 mols
Number of H atoms = 8 x 0.02 x 6 x 10^23
= 9.6 x 10^22
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