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secondary 3 | A Maths
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Pls helo me find the coordinates of B and D asap thx
Date Posted: 2 years ago
Views: 344
AB line
y = - ⅓ ∙ x - ¹⁷⁄₃
AD line
y = 3 ∙ x + 1
- ⅓ ∙ x - ¹⁷⁄₃ = 3 ∙ x + 1
point A(-2 , -5)
-x-17 = 9x+3
x = -2
y = -5
CD line
y = - ⅓ ∙ x - d
BC line
y = 3 ∙ x + b
3 = - ⅓ ∙ 4 - d
9 = -4 - 3d
d = -¹³⁄₃
3 = 3 ∙ 4 + b
b = -9
CD line
y = - ⅓ ∙ x + ¹³⁄₃
BC line
y = 3 ∙ x - 9
B (1 , -6) → BC line ~ AB line
y = 3 ∙ x - 9
y = - ⅓ ∙ x - ¹⁷⁄₃
- ⅓ ∙ x - ¹⁷⁄₃ = 3 ∙ x - 9
-x-17 = 9x - 27
x = 1
y = -6
D (1 , 4) → CD line ~ AD line
y = 3 ∙ x + 1
y = - ⅓ ∙ x + ¹³⁄₃
- ⅓ ∙ x + ¹³⁄₃ = 3 ∙ x + 1
-x+13 = 9x+3
x = 1
y = 4
y = - ⅓ ∙ x - ¹⁷⁄₃
AD line
y = 3 ∙ x + 1
- ⅓ ∙ x - ¹⁷⁄₃ = 3 ∙ x + 1
point A(-2 , -5)
-x-17 = 9x+3
x = -2
y = -5
CD line
y = - ⅓ ∙ x - d
BC line
y = 3 ∙ x + b
3 = - ⅓ ∙ 4 - d
9 = -4 - 3d
d = -¹³⁄₃
3 = 3 ∙ 4 + b
b = -9
CD line
y = - ⅓ ∙ x + ¹³⁄₃
BC line
y = 3 ∙ x - 9
B (1 , -6) → BC line ~ AB line
y = 3 ∙ x - 9
y = - ⅓ ∙ x - ¹⁷⁄₃
- ⅓ ∙ x - ¹⁷⁄₃ = 3 ∙ x - 9
-x-17 = 9x - 27
x = 1
y = -6
D (1 , 4) → CD line ~ AD line
y = 3 ∙ x + 1
y = - ⅓ ∙ x + ¹³⁄₃
- ⅓ ∙ x + ¹³⁄₃ = 3 ∙ x + 1
-x+13 = 9x+3
x = 1
y = 4
See 2 Answers
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Date Posted:
2 years ago
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Hi, Lee. I hope it helps
Date Posted:
2 years ago
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