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junior college 1 | H2 Maths
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Angelica
Angelica

junior college 1 chevron_right H2 Maths

H2 chemistry help for q2 pls

Date Posted: 7 years ago
Views: 435
Ryan Ong Meng How
Ryan Ong Meng How
7 years ago
Read the comment of my answer, I've made a mistake in the original answer sorry! ><

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Ryan Ong Meng How
Ryan Ong Meng How's answer
4 answers (Tutor Details)
1st
First thing you need to note is that the ratio of partial pressure is not affected by the molecular mass of the compounds. It's only affected by the number of atoms.

Thus we can effectively say that every 2atm of NH3 would mean a loss of 1atm N2 and 3atm H2.

So at the start from the ratio there is 200atm and the partial pressure of both gases are..

N2:H2 > 1:3 > 50:150
Then the lost of N2 = (27/2)*1=13.5
And the lost of H2 = (27/2)*3=40.5
So the Kp=(NH3)/(N2)(H2)
=(27)/(50-13.5)(150-40.5)
=6.755*10^-3
Ryan Ong Meng How
Ryan Ong Meng How
7 years ago
Oops I made a mistake
Kp=(NH3)^2/(N2)(H2)^3
Thus it is actually equals to...
Kp=27^2/(50-13.5)(150-40.5)^3
=1.52*10^-5
Angelica
Angelica
7 years ago
Thanks alot!!!