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primary 6 | Maths
| Data Analysis
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Please help! Thanks!
Date Posted: 1 year ago
Views: 362
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It can also be solved easily by algebra in sec1 by assuming casey’s speed = X and Jon’s speed = (X +23), then you would have equation 5 (X) = 4 (X +23) and get X =92, where you can calculate PQ = 5X = 460 and PR = 2 PQ = 920 (km)
It can also be solved easily by algebra in sec1 by assuming casey’s speed = X and Jon’s speed = (X +23), then you would have equation 5 (X) = 4 (X +23) and get X =92, where you can calculate PQ = 5X = 460 and PR = 2 PQ = 920 (km)
Date Posted:
1 year ago
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