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secondary 4 | E Maths
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hello,can someone pls help me with this question ?
Date Posted: 2 years ago
Views: 248
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done
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Hope this helps
Date Posted:
2 years ago
thankyouu :)))
hello,is it okay if you explain step one ？
cube root = index notation ⅓
So, (2³)⅓ = 2 and 2^6n ^⅓ = 2^3n
So, (2³)⅓ = 2 and 2^6n ^⅓ = 2^3n
ohh okay, thankyouu so much !!
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