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secondary 3 | E Maths
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someone please help me with ciii). tysm <33
Date Posted: 2 years ago
Views: 217
We just make guesses for this one since the question asks us to simply “write down” the answer.
We randomly find a number in the list which gives a remainder of 7 when divided by 11.
11 x 90 = 990
990 + 7 = 997
The next number in the list, 1008, is a qualifying number.
11 x 900 = 9900
11 x 909 = 9999
9999 + 7 = 10006 (exceeded)
The number before this, 9995, is a qualifying number.
We randomly find a number in the list which gives a remainder of 7 when divided by 11.
11 x 90 = 990
990 + 7 = 997
The next number in the list, 1008, is a qualifying number.
11 x 900 = 9900
11 x 909 = 9999
9999 + 7 = 10006 (exceeded)
The number before this, 9995, is a qualifying number.
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Anything you don’t understand please let me know thanks!
Date Posted:
2 years ago
thank youu!!
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