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secondary 3 | E Maths
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Hii how do I do this qn?
Date Posted: 1 year ago
Views: 334
take the 41st root of every number ...
(3^82)^(1/41) = 3^2 = 9
(2^164)^(1/41) = 2^4 = 16
(5^41)^(1/41) = 5^1 = 5
since 5<9<16,
then (5^41)<(3^82)<(2^164)
(3^82)^(1/41) = 3^2 = 9
(2^164)^(1/41) = 2^4 = 16
(5^41)^(1/41) = 5^1 = 5
since 5<9<16,
then (5^41)<(3^82)<(2^164)
Sorry I don’t really understand
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