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secondary 4 | A Maths
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lucas
Lucas

secondary 4 chevron_right A Maths chevron_right Singapore

functions

Date Posted: 2 years ago
Views: 369

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Jackson Wan
Jackson Wan's answer
18 answers (Tutor Details)
1st
y=2x^2+6x-1
use completing the square
y=2(x+3/2)^2-2(3/2)^2-1
=2(x+3/2)^2-9/2-1
=2(x+3/2)^2-11/2.

when x=-3/2, y=-11/2

Vertex= ( -3/2, -11/2)

axis od symmetry x= -3/2

y-intercept(when x=0) = 2(9/4)-11/2 = -1

new curve:f'(x)=

f(x)*2*-1 +3= -4x^2-12x+1

new vertex: (-3/2, 13)

hope this helps