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secondary 4 | A Maths
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Anyone able to help! Thank you :(
Date Posted: 1 year ago
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Let m = Arctan (sq root 3 / 2)
= 40.89 deg
So, the principal values of m are:
bigger than - 90 deg and smaller than +90 deg
In terms of Pi,
m is larger than -Pi/2
and
m is smaller than +Pi/2
= 40.89 deg
So, the principal values of m are:
bigger than - 90 deg and smaller than +90 deg
In terms of Pi,
m is larger than -Pi/2
and
m is smaller than +Pi/2
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