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secondary 3 | A Maths
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It is a simultaneous equation question.
Date Posted: 7 years ago
Views: 620
Make 2y the subject from eqn 1
2y=3x-1
Sub 2y=3x-1 in to (2y+3)
new eqn (x-2)^2+(3x-1+3)^2=26
Open up the squares.
Then solve for x using the quadratic formula or chopstick method( can check which to use by doing the b^2-4ac).
Lastly,need Tuition can look for me:)
2y=3x-1
Sub 2y=3x-1 in to (2y+3)
new eqn (x-2)^2+(3x-1+3)^2=26
Open up the squares.
Then solve for x using the quadratic formula or chopstick method( can check which to use by doing the b^2-4ac).
Lastly,need Tuition can look for me:)
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