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## Question

secondary 3 | A Maths

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It is a simultaneous equation question.

2y=3x-1

Sub 2y=3x-1 in to (2y+3)

new eqn (x-2)^2+(3x-1+3)^2=26

Open up the squares.

Then solve for x using the quadratic formula or chopstick method( can check which to use by doing the b^2-4ac).

Lastly,need Tuition can look for me:)

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