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secondary 3 | A Maths
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Koh Yun Zhen
Koh Yun Zhen

secondary 3 chevron_right A Maths

It is a simultaneous equation question.

Date Posted: 2 years ago
Views: 201
Chen Kang
Chen Kang
2 years ago
Make 2y the subject from eqn 1
2y=3x-1
Sub 2y=3x-1 in to (2y+3)
new eqn (x-2)^2+(3x-1+3)^2=26
Open up the squares.
Then solve for x using the quadratic formula or chopstick method( can check which to use by doing the b^2-4ac).
Lastly,need Tuition can look for me:)

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WEE SOO JUN
Wee Soo Jun's answer
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