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secondary 4 | A Maths
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Can someone help to solve qA
Date Posted: 1 year ago
Views: 267
I don't have a calculator with me now to solve this but to solve this.
Look at straight line y-2x=3
Let y = 3+2x and x = ( y - 3 )/2
Then sub the X=(y-3)/2 into the curve to get
2x^2 + (3+2x)^2 -4x = 39
and solve X from there using the quadratic formula.
Do the same for y=3+2x to find Y
You should have 2 sets of X and Y coordinates
Look at straight line y-2x=3
Let y = 3+2x and x = ( y - 3 )/2
Then sub the X=(y-3)/2 into the curve to get
2x^2 + (3+2x)^2 -4x = 39
and solve X from there using the quadratic formula.
Do the same for y=3+2x to find Y
You should have 2 sets of X and Y coordinates
Thank , should be able to solve it
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