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primary 6 | Maths
| Fractions
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This is a science question, not math
Date Posted: 2 years ago
Views: 465
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I'm going to assume that the set-up is placed vertically (such that the iron ball can "fall off" by gravity if it somehow rolls out of the iron contacts).
Notice carefully that if the iron ball is "missing" from the iron contacts, then the portion of the circuit between the batteries and switch S1 would be "broken". In short, if the iron ball is missing, the circuit would not be complete since there is no complete looping path from the batteries back into the batteries.
When S1 and S2 are closed, there will be a complete circuit at that point of time. This causes the iron rod to "charge up" its magnetism and become a magnet. At this point, the iron rod has magnetic abilities and will be able to attract the iron ball. We will assume that the attraction force is stronger than the gravitational (downward force) so that the iron ball is able to move upwards.
However, as soon as the iron ball leaves the iron contacts (in its pursuit of moving towards the iron rod), the path between the batteries and switch S1 would be broken. Then, the path leading to the battery would be broken. Electricity stops flowing as a result, and the iron rod loses its magnetic ability.
This results in the iron ball no longer being attracted to the iron rod, so it falls off towards the iron contacts. But the moment the ball hits the iron contacts, the circuit is once again complete, charging up the iron rod again.
What do you think happens next?
P.S. The light bulb below will be lighting on and off continuously as well, though this is not needed for part (a).
Notice carefully that if the iron ball is "missing" from the iron contacts, then the portion of the circuit between the batteries and switch S1 would be "broken". In short, if the iron ball is missing, the circuit would not be complete since there is no complete looping path from the batteries back into the batteries.
When S1 and S2 are closed, there will be a complete circuit at that point of time. This causes the iron rod to "charge up" its magnetism and become a magnet. At this point, the iron rod has magnetic abilities and will be able to attract the iron ball. We will assume that the attraction force is stronger than the gravitational (downward force) so that the iron ball is able to move upwards.
However, as soon as the iron ball leaves the iron contacts (in its pursuit of moving towards the iron rod), the path between the batteries and switch S1 would be broken. Then, the path leading to the battery would be broken. Electricity stops flowing as a result, and the iron rod loses its magnetic ability.
This results in the iron ball no longer being attracted to the iron rod, so it falls off towards the iron contacts. But the moment the ball hits the iron contacts, the circuit is once again complete, charging up the iron rod again.
What do you think happens next?
P.S. The light bulb below will be lighting on and off continuously as well, though this is not needed for part (a).
Stranger, in your answer, you must include the fact that
- a complete circuit causes the iron rod to become magnetised and attract the iron ball
- the iron rod loses its magnetism as soon as current stops flowing (due to the breakage of the circuit)
I am no P6 science expert on this (and I am not familiar with the way marks are allocated for primary level science questions), but this is a rough idea to consider.
- a complete circuit causes the iron rod to become magnetised and attract the iron ball
- the iron rod loses its magnetism as soon as current stops flowing (due to the breakage of the circuit)
I am no P6 science expert on this (and I am not familiar with the way marks are allocated for primary level science questions), but this is a rough idea to consider.
Kai, I doubt that primary science students learn about predicting the polarities of the magnet when the magnet is placed in a solenoid (if I interpret "leading to different poles of the magnet" correctly).
The polarity of the magnet can be either North or South - either way, it's going to create an effect of induced magnetism in the iron ball such that the ball will get attracted to the rod.
The polarity of the magnet can be either North or South - either way, it's going to create an effect of induced magnetism in the iron ball such that the ball will get attracted to the rod.
Wished you were my science cher sia
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