Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 3 | Physics
One Answer Below
Anyone can contribute an answer, even non-tutors.
Example 9. Tysm
Date Posted: 2 years ago
Views: 588
Weight of the object
= mg
= 4.0 x 10
= 40 N
[On earth, g = 10 N/kg]
Object moves with a constant VELOCITY, so object is not accelerating at all (a = 0).
By F = ma and using the fact that a = 0, the resultant horizontal force acting on the object must be zero.
This means that the object's forward force is equal to the frictional force, but the object is sliding on a "smooth" (counted as frictionless) surface, so there is not even a need for any applied force to get the object moving at constant velocity.
So, zero force is required to keep the block moving.
The resultant force acting on the object must be zero as well (not just the horizontal portion) because the block does not simply "sink into the ground" due to its weight.
= mg
= 4.0 x 10
= 40 N
[On earth, g = 10 N/kg]
Object moves with a constant VELOCITY, so object is not accelerating at all (a = 0).
By F = ma and using the fact that a = 0, the resultant horizontal force acting on the object must be zero.
This means that the object's forward force is equal to the frictional force, but the object is sliding on a "smooth" (counted as frictionless) surface, so there is not even a need for any applied force to get the object moving at constant velocity.
So, zero force is required to keep the block moving.
The resultant force acting on the object must be zero as well (not just the horizontal portion) because the block does not simply "sink into the ground" due to its weight.
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Hi, I provide 1 to 1 tuition, $80/1.5h, can cover English / Maths / Science / Physics, ex-school teacher, can produce teaching cert from NIE, WhatsApp 9033 8810 :)
Date Posted:
2 years ago
360 Tutoring Program