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primary 6 | Maths
| Fractions
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Date Posted: 1 year ago
Views: 305
left →
G(¼) : B(⅕)
= 1u+49 : 1u
at first →
G:B:G+B
= 4(1u+49) : 5u : 9u+4×49
9u+4×49 = 403
u = (403-4×49)÷9 = 23
403-5u
= 288 (Ans)
G(¼) : B(⅕)
= 1u+49 : 1u
at first →
G:B:G+B
= 4(1u+49) : 5u : 9u+4×49
9u+4×49 = 403
u = (403-4×49)÷9 = 23
403-5u
= 288 (Ans)
See 1 Answer
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