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secondary 3 | A Maths
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need help for part c
Date Posted: 1 year ago
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(c)
times "3xy" at both sides of equation 2
2x - 3y = 6xy
3y - x= 3 ⇨ x = 3y-3
(y-1) ∙(1-6y) = 1
6y² -7y +2 = 0
(3y-2)∙(2y-1) = 0
y₁ = ⅔ → x₁ = -1
y₂ = ½ → x₂ = -³⁄₂
Ans
(x₁ , y₁) = (-1 , ⅔ )
(x₂ , y₂ ) = (-³⁄₂ , ½ )
times "3xy" at both sides of equation 2
2x - 3y = 6xy
3y - x= 3 ⇨ x = 3y-3
(y-1) ∙(1-6y) = 1
6y² -7y +2 = 0
(3y-2)∙(2y-1) = 0
y₁ = ⅔ → x₁ = -1
y₂ = ½ → x₂ = -³⁄₂
Ans
(x₁ , y₁) = (-1 , ⅔ )
(x₂ , y₂ ) = (-³⁄₂ , ½ )
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