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secondary 3 | A Maths
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Hi I rlly need help with part ii) pls !!! Thank youu
Date Posted: 1 year ago
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Actually for part ii it just requires substitution of the smallest positive integer of m from the range of m obtained in part ii into the original equations to find the point of intersection. You will need to exclude the other inequality as m needs to be more than 0 for this question since we are finding a positive integer. part i is more challenging if you struggle with solving inequalities.
Date Posted:
1 year ago
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