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secondary 4 | A Maths
2 Answers Below
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need help with this qn, pls explain too
Date Posted: 2 years ago
Views: 456
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when a^2 = b,
have to consider both positive & negative roots,
so a =±sqrt[b].
(lnx)^2 = ln20
ln x = ±sqrt[ln20]
x = e^(±sqrt[ln20])
= 5.6453 or 0.1771
both values can satisfy the original equation.
there are 2 possible solutions!
have to consider both positive & negative roots,
so a =±sqrt[b].
(lnx)^2 = ln20
ln x = ±sqrt[ln20]
x = e^(±sqrt[ln20])
= 5.6453 or 0.1771
both values can satisfy the original equation.
there are 2 possible solutions!
done
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Okee thx!
Date Posted:
2 years ago
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