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Question
primary 6 | Maths
| Fractions
2 Answers Below
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had in total
(1-¹⁹⁄₅₀)×(10×5u+200)
= ³¹⁄₅₀×(50u+200)
= 31u + 124
3 weeks (21 days) →
31u+124 - 50u = 124-19u
124-19u = 21×5u
u = 124÷(21×5+19) = 1
5u = 5
50×5 = 250 (Ans)
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