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Question
primary 5 | Maths
| Fractions
2 Answers Below
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Date Posted: 2 years ago
Views: 380
$ each →
1 R → 1u
1 N → 2u
2N+3R = 2×2u+3×1u = 7u → ⅓
$ total → 3×7u = 21u
21u ÷ 1u = 21 (Ans)
1 R → 1u
1 N → 2u
2N+3R = 2×2u+3×1u = 7u → ⅓
$ total → 3×7u = 21u
21u ÷ 1u = 21 (Ans)
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