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primary 6 | Maths
| Data Analysis
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Date Posted: 2 years ago
Views: 356
(a) 75
(b) $28.50
(b) $28.50
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I found the solution. Thank for your help
20¢ → ⅗ = ⁶⁄₁₀
50¢ → ⅖ = ⁶⁄₁₅
$5.40÷($0.50-$0.20) = 18
18÷6 = 3
(a)
(10+15)×3 = 75 (Ans)
(b)
3×(10×$0.20 + 15×$0.50)
= $28.50 (Ans)
50¢ → ⅖ = ⁶⁄₁₅
$5.40÷($0.50-$0.20) = 18
18÷6 = 3
(a)
(10+15)×3 = 75 (Ans)
(b)
3×(10×$0.20 + 15×$0.50)
= $28.50 (Ans)
See 2 Answers
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20¢ → ⅗ = ⁶⁄₁₀
50¢ → ⅖ = ⁶⁄₁₅
$5.40÷($0.50-$0.20) = 18
18÷6 = 3
(a)
(10+15)×3 = 75 (Ans)
(b)
3×(10×$0.20 + 15×$0.50)
= $28.50 (Ans)
6u = $5.40÷3 = $1.80
$1.80÷$0.10 = 18 ⇨
50¢ → 5×(18÷2) = 45
20¢ → 5×(18÷3) = 30
(a) 45+30 = 75 (Ans)
(b) 45×$0.50+30×$0.20 = $28.50 (Ans)
50¢ → ⅖ = ⁶⁄₁₅
$5.40÷($0.50-$0.20) = 18
18÷6 = 3
(a)
(10+15)×3 = 75 (Ans)
(b)
3×(10×$0.20 + 15×$0.50)
= $28.50 (Ans)
6u = $5.40÷3 = $1.80
$1.80÷$0.10 = 18 ⇨
50¢ → 5×(18÷2) = 45
20¢ → 5×(18÷3) = 30
(a) 45+30 = 75 (Ans)
(b) 45×$0.50+30×$0.20 = $28.50 (Ans)
Date Posted:
2 years ago
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use algebra for the following problem
Date Posted:
2 years ago
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